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std::accumulate in C++

Published: 23-10-2019 | Author: Remy van Elst | Text only version of this article

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I'm using codewars to practice my development skills. Today I found out about the std::accumulate method in C++ while doing an exercise there. I'm sharing it here because I never heard of it before. It is the <numeric> header, and it also accepts a custom binary function to apply instead of operator+. This snippet shows some examples including a lambda operator and the for loop you would use otherwise.

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Plain old loop

It performs a fold on a given range. Or, in my case, it gives the sum of all int's in a vector without a loop. Complete documentation here.

Consider this code:

std::vector <int> numbers  { 20, 10, -8, 10, 10, 15, 35 };
int sum = 0;
for (auto const& number: numbers)
    sum += number;
std::cout << "sum: " << sum;

The output after compiling is:

# C:\Users\Remy\CLionProjects\codewars\cmake-build-debug\src\CodeWars.exe

sum: 92

This can be written shorter using the accumulate function:

int sum = std:accumulate(numbers.begin(), numbers.end(), 0);

std::accumulate accepts an initial value, so to add 10 to the result of the above sum without an intermidiate variable:

std::vector <int> numbers  { 20, 10, -8, 10, 10, 15, 35 }; 
int sum = std:accumulate(numbers.begin(), numbers.end(), 10);

The result will be 102.


std::accumulate also accepts a function to perform as the fold operator. For example, if you need to get a sum of the result and also multiply every number by 8, in the odd case you need to go from bytes to bits:

std::vector <int> numbers  { 10, 20, 30 };
int sum = std::accumulate(numbers.begin(), 
        [](int a, int b) { return a + (b*8);}
std::cout << "sum: " << sum;


sum: 480

The binary operator takes the current accumulation value a (initialized to init) and the value of the current element b.

This is a simple example of course, but by using a lambda you can do all kinds of crazy stuff.

From the documentation, on reversing the order:

std::accumulate performs a left fold. In order to perform a right fold, 
one must reverse the order of the arguments to the binary operator, and 
use reverse iterators. 
Tags: c++ , codewars , cpp , development , snippets